13. BeeQaa
(Off)
[ 15 Feb 2021, 17:09 ]
NEO,
შენი კოდიდან გამომდინარე ასე ჩასვი
if (isset($_GET['id']
$anketa=get_user(intval($_GET['id']

;
else
$anketa=get_user($user['id']);
$k_post=mysql_result(mysql_query("SELECT COUNT(*) FROM `status` WHERE `id_user` = '".$anketa['id']."'"),0);
$k_page=k_page($k_post,$set['p_str']);
$page=page($k_page);
$start=$set['p_str']*$page-$set['p_str'];
$q=mysql_query("SELECT * FROM `status` WHERE `id_user` = '".$anketa['id']."' ORDER BY `id` DESC LIMIT 1");
echo "<table class='post'>\n";
if ($k_post==0)
{
echo "<div class='nav1'>\n";
echo "სტატუსი არაა\n";
echo "</div>\n";
}
while ($post = mysql_fetch_assoc($q
{
$ank=mysql_fetch_assoc(mysql_query("SELECT * FROM `user` WHERE `id` = $post[id_user] LIMIT 1"));
/*-----------зебра-----------*/
if ($num==0){
echo '<div class="nav1">';
$num=1;
}
/*---------------------------*/
echo '<div class="str_2">';
echo output_text($post['msg']);
echo "</div>";
echo "<a href='komm.php?id=$post[id]'><img src='/style/icons/bbl4.png' alt=''/>" . mysql_result(mysql_query("SELECT COUNT(*) FROM `status_komm` WHERE `id_status` = '$post[id]'"),0) . "</a> ";
if ($post['pokaz']==0){
}else{
if (isset($user) && ($user['level']>$ank['level'] || $user['level']!=0 || $user['id']==$ank['id']))
echo " <font color='green'>დაყენებულია</font>\n";
if (isset($user) && ($user['level']>$ank['level'] || $user['level']!=0 || $user['id']==$ank['id']))
echo " [<a href=\"user/status/delete.php?id=$post[id]\"><img src='/style/icons/delete.gif' alt=''/> წაშლა</a>]\n";
}
echo '</div>';
}
echo "</table>\n";
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